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4 years ago

14 - 2(3p + 1) = 6(4/p)

Mathematics

1 answer:

GuDViN [60]4 years ago

3 0

Is it divide after the equal sign? I will text you on message. follow me

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The figure is made up of a rectangle and 2 right triangles.

sladkih [1.3K]

<span>1259 units2 i hope this helps you</span>

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3 years ago

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A rectangle measures 18 cm x 3 cm what is its area

s344n2d4d5 [400]

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Six

Step-by-step explanation:

The answer could be shown in multiple forms, but if I'm correct, the answer to this problem would be six.

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3 years ago

In order to make a safe parachute landing from a mountain top, you must be at least 9,000 feet in the air. At the top of Mount M

7nadin3 [17]

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Evaluate the following expression:<br> -X- 6x + 10 when x = 5

BigorU [14]

Answer:

-25

Step-by-step explanation:

Evaluate -x - 6 x + 10 where x = 5:

-x - 6 x + 10 = -5 - 6×5 + 10

-6×5 = -30:

-5 + -30 + 10

-5 - 30 + 10 = 10 - (5 + 30):

10 - (5 + 30)

5 + 30 = 35:

10 - 35

10 - 35 = -(35 - 10):

-(35 - 10)

| 3 | 5

- | 1 | 0

| 2 | 5:

Answer: -25

8 0

3 years ago

Help help help pls :)

kykrilka [37]

Answer:

$opposite\approx 70.02$

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Please note that the names ( $opposite$ ) and ( $adjacent$ ) are subjective and change depending on the angle one uses in the ratio. However the name ( $hypotenuse$ ) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent ( $tan$ ) ratio.