Answer: E
=
1.55
⋅
10
−
19
J
Explanation:
The energy transition will be equal to 1.55
⋅
10
−
1
J
.
So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition
1
λ =
R
⋅
(
1
n
2
final −
1
n
2
initial )
, where
λ
- the wavelength of the emitted photon;
R
- Rydberg's constant - 1.0974
⋅
10
7
m
−
1
;
n
final
- the final energy level - in your case equal to 3;
n
initial
- the initial energy level - in your case equal to 5.
So, you've got all you need to solve for λ
, so
1
λ =
1.0974
⋅10 7
m
−
1
⋅
(....
−152
)
1
λ
=
0.07804
⋅
10
7
m
−
1
⇒
λ
=
1.28
⋅
10
−
6
m
Since
E
=
h
c
λ
, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by
h
⋅
c
, where
h
- Planck's constant -
6.626
⋅
10
−
34
J
⋅
s
c
- the speed of light -
299,792,458 m/s
So, the transition energy for your particular transition (which is part of the Paschen Series) is
E
=
6.626
⋅
10
−
34
J
⋅
s
⋅
299,792,458
m/s
1.28
⋅
10
−
6
m
E
=
1.55
⋅
10
−
19
J
Answer:
k = 4,92x10⁻³
Explanation:
For the reaction:
AB₂C (g) ⇄ B₂(g) + AC(g)
The equilibrium constant, k is defined as:
![k = \frac{[B_{2}][AC]}{[AB_2C]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5BB_%7B2%7D%5D%5BAC%5D%7D%7B%5BAB_2C%5D%7D)
<em>(1)</em>
Molar concentration of the species are:
[AB₂C]: 0,0840mol / 5L = <em>0,0168M</em>
[B₂]: 0,0350mol / 5L = <em>0,0070M</em>
[AC]: 0,0590mol / 5L = <em>0,0118M</em>
Replacing this values in (1):
![k = \frac{[0,0070][0,0118]}{[0,0168]}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B%5B0%2C0070%5D%5B0%2C0118%5D%7D%7B%5B0%2C0168%5D%7D)
<em>k = 4,92x10⁻³</em>
I hope it helps!
Answer:
1 and 3 i think so i could be wrong
Your answer is B and the element is Carbon
So what your looking for is matching isotopes. Isotopes are elements that are the same in amount of protons but different in mass meaning different number in neutrons. Because when you add the total protons and neutrons together you get your atomic mass. So this can be written as X=said element, top number above=different atomic mass, bottom number below=atomic number. Hope this help!!
Be careful because answer A has same masses but different atomic numbers so different atoms(elements)!!!
