<h2>Frequency</h2>
Explanation:
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
Wave speed is the speed at which a wave travels.
Let the wave speed be 
Let the wave frequency be 
Let the wave length be 
The wave speed,frequency and wave length are related by the equation 
.
When increases, increases on the other side to maintain equality when no other property is changing.
Answer:
C. CH3COOH, Ka = 1.8 E-5
Explanation:
analyzing the pKa of the given acids:
∴ pKa = - Log Ka
A. pKa = - Log (1.0 E-3 ) = 3
B. pKa = - Log (2.9 E-4) = 3.54
C. pKa = - Log (1.8 E-5) = 4.745
D. pKa = - Log (4.0 E-6) = 5.397
E. pKa = - Log (2.3 E-9) = 8.638
We choose the (C) acid since its pKa close to the expected pH.
⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):
- pH = pKa + Log ([CH3COO-]/[CH3COOH])
∴ pH = 4.5
∴ pKa = 4.745
⇒ 4.5 = 4.745 + Log ([CH3COO-]/[CH3COOH])
⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])
⇒ 0.5692 = [CH3COO-]/[CH3COOH]
∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]
⇒ 1.8 E-5 = [H3O+](0.5692)
⇒ [H3O+] = 3.1623 E-5 M
⇒ pH = - Log ( 3.1623 E-5 ) = 4.5
Physical<span> changes involve a new </span>form<span> or shape of matter,
</span>
Chemical change<span> is any </span>change<span> that results in the formation of new </span>chemical<span> substances.</span>
Answer:
From the equation you will see that 1 mol of propane generates 4 mols of water.
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
Explanation:
Since the molar mass of water
M
(
H2O)=2×1+16=18g/mol
2 mol propane will generate
2
×4×18=144g of water
The atmosphere is considered homogeneous. It isn’t exactly on the smallest scales but that doesn’t matter. Homogenous means the composition will be the same in any sample taken from the substance. And clearly, the atmosphere is mostly gas. So the last answer is right
