On the basis of your understanding of the general solubility guidelines, predict which of the following substances are likely to
1 answer:
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Answer:
1.047 M
Explanation:
The given reaction:
For dichromate :
Molarity = 0.254 M
Volume = 15.8 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 15.8 ×10⁻³ L
Thus, moles of dichromate :
Moles of dichromate = 0.0040132 moles
1 mole of dichromate react with 6 moles of iron(II) solution
Thus,
0.0040132 moles of dichromate react with 6 × 0.0040132 moles of iron(II) solution
Moles of iron(II) solution = 0.02408 moles
Volume = 23 mL = 0.023 L
Considering:
<u>Molarity = 0.02408 / 0.023 = 1.047 M</u>