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2 years ago

I’m taking a college algebra test tomorrow and I am super scared. Any advice? Thank you!!

Mathematics

2 answers:

Naily [24]2 years ago

7 0

Answer:

pray to god about it and go sit somewhere quiet and think

Step-by-step explanation:

OleMash [197]2 years ago

5 0

Answer:

Think the algebra throught carefully .<u> Eliminate x</u>

Step-by-step explanation:

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The experiment proceeded as normal, with the experimental group hearing about the potential presence of a gun as the confederate

Vika [28.1K]

Answer:

The answer is "The threat to internal validity is mortality".

Step-by-step explanation:

It signifies that while in terms of your study, persons were "morning." It usually signifies when people leave the studies. There will be only likely if indeed the experiment lasts a long period that it'll be a substantial danger to validity and reliability because the chance for drops increases. Eight content validity risks are history, maturity, instrument, test, choice, average regress, human engagement, and mortality.

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3 years ago

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

2 years ago

Chelsea wrote several equations and determined that only one of the equations has exactly one solution. Which of these

Aneli [31]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Simplify the given equation.

xxMikexx [17]

When simplified,letter A will be your answer.
4-7x=15

6 0

3 years ago

arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

8 0

2 years ago