Answer:
435=107+82+246
Step-by-step explanation:
I think this is correct. Someone correct me if I am wrong, but I took 435 and subtracted 107, then I took that number and divided it by 4 and took one of those 4 and put it in the equation then multiplied the last three.
Answer:
C) 2
Step-by-step explanation:
step 1: Find mean of data set
2+4+4+5+7+8 = 30
30/6 = 5
Mean = 5
step 2: subtract each data value from the mean and square it
5-2 = 3; 3² = 9
5-4 = 1; 1² = 1
5-4 = 1; 1² = 1
5-5 = 0; 0² = 0
5-7 = -2; (-2²) = 4
5-8 = -3; (-3²) = 9
Add the squared results:
9+1+1+0+4+9 = 24
Divide 24 by 6 to get the Variance of 4
Take the square root of the Variance to get the Standard Deviation
= 2
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
60a^5 is the answer to your question
The answer is 10x+9y+6 if your trying to combine all like terms.