Answer:
<h2>x = -7 and y=8</h2>
Step-by-step explanation:
<h2> soln</h2><h2>using by elimination method</h2><h2> 1|x+2y=9</h2><h2> 1| x+y=1</h2><h2> |x+2y=9</h2><h2> -|x+y=1</h2><h2> x-x+2y-y=9-1</h2><h2> 0+y=8</h2><h2> y=8</h2>
<h2> 1|x+2y=9</h2><h2> 2|x+y=1</h2>
<h2> |x+2y=9</h2><h2> -|2x+2y=2</h2>
<h2>x-2x+2y+2y=9-2</h2>
<h2>-x=7</h2><h2>divide -1 both side with the make value of x</h2><h2>x=-7</h2><h2>therefore x=-7 and y=8. this is my answer</h2>
Given:
CH = 3960 miles
Altitude = 240 miles
To find:
The distance from the space station to the horizon.
Solution:
The reference image for answer is attached below.
Radius = 3960 miles
CD = CH = 3960
ED = 240
EC = CD + ED
= 3960 + 240
EC = 4200 miles
By Pythagorean theorem:
Subtract 15681600 from both sides.
Taking square root on both sides, we get
The distance from space station to the horizon is approximately 1400 miles.
3/12 is rational because it ends in 0.25
Answer:
Step-by-step explanation:
-8 + 6(b - 1) = -8 +6b-6 = 6b -14
Hello there!
So, let's start off with the first one:
A) 60% of One - half x
I believe a couple of possible equations would be: 0.60*1/2x or 0.60*0.5x. 1/2 and 0.5 both equal half of a number. The 0.60 would equal 60%. I'll plug 10 into x of both equations to see what I come up with:
First Equation:
1/2 * 10/1 = 10/2 or 5.
0.60 * 5 = 3
Second Equation:
0.5 * 10 = 5
0.60 * 5 = 3
So they both come up with the same answer, so that makes them both equal, which makes them both possible equations.
B) 7 times z reduced by a third of the product
7z - 1/3 seems like a good equation. Let me plug in 5 for z to solve:
7 * 5 = 35
Convert 35/1 into 105/3 by multiplying both sides by 3
105/3 - 1/3 = 104/3 (approx. 34.7)
C) Three-fourths of V subtracted from 6 times two-ninths
A good equation for this would probably be (6*2/9)-3/4v. I'll plug 5 into v to show how we would solve the equation:
6/1 * 2/9 = 12/9 or 1 1/3.
3/4 * 5/1 = 15/4 or 3 3/4.
(Use the fractions 16/12 and 45/12 as 16/12 = 12/9 and 15/4 = 45/12)
16/12 - 45/12 = -29/12 or −<span>2 <span>5/12</span></span>
D) Sum of 2x, (2/3 + 5) and 11-x
I think the right equation for this would be 2x + (2/3 + 5) + 11-x. Plug in 3 for x to solve:
(Use 15/3 when adding 2/3 and 5 because 5 = 15/3)
2/3 + 15/3 = 17/3 or 5 2/3
2 * 3 = 6
11 - 3 = 8
(Use 18/3 and 24/3 when adding up 6 + 5 2/3 + 8 as 6 = 18/3 and 8 = 24/3
17/3 + 18/3 + 24/3 = 59/3 or 19 2/3
Sorry if this confused you xD but, basically, the possible equations are as follows:
1 = 0.60*1/2x or 0.60*0.5x
2 = 7z - 1/3
3 = <span>(6*2/9)-3/4v
</span>4 = 2x + (2/3 + 5) + 11-x
I hope this helped! If not, I'm very sorry. Algebra isn't my strong suit ^.^'
