Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
I think it's around 9.8 or something
Step-by-step explanation:
sqrt(100) is 10
so the sqrt(95) should be around 9.8
Answer:
D
Step-by-step explanation:
Slope = (y2 - y1) / (x2 - x1)
= (2 - 0) / (0 - (-3)
= 2/3
Y intercept 2
Let m = 10 and n = 2
We know:
y^2 = (m+n).m
y^2 = (10+2).10
y^2 = 120
y = √(120)
Then,
m^2 + x^2 = y^2
10^2 + x^2 = ( √( 120) )^2
100 + x^2 = 120
x^2 = 120 - 100
x^2 = 20
x = √(20)
x = √(4×5)
x = √(4) × √(5)
x = 2√(5)
I hope this has helped!
2a²b³ and -4a²b³ are like terms as they both have the same variables with the same degrees.
Your final answer is a. True.
