Translate the shape A three squares right and one square up.

Mathematics

2 answers:

SOVA2 [1]2 years ago

3 0

Answer:

(4, 3) , (4, 0) , (6, 0)

Step-by-step explanation:

M (1, 4)

M ' ( 1 + 3, 4 - 1)

namely M ' (4, 3)

N (1, 1)

N ' ( 1 + 3 , 1 - 1) ((x, y) 3 squares right and 1 square down means

namely n" (4, 0) ( x + 3, y - 1))

p (3, 1)

p ' ( 3 + 3 , 1 - 1)

namely p' (6, 0)

uranmaximum [27]2 years ago

3 0

Step-by-step explanation:

(3,4) not that sure about the coordinates are right

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Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm t

Angelina_Jolie [31]

The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)

[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²

Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N

Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
Units have to be consistent ... so have to convert 75.0 cm to m: 

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Clim_%7Bh%20%5Cto%20%5C116%7D%20x-16%2F%5Csqrt%7Bx%7D%20-4" id="TexFormula1" title="\lim_{h

Evgen [1.6K]

Answer:

$\displaystyle 8$

Step-by-step explanation:

we would like to compute the following limit

$\displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \right)$

if we substitute 16 directly we'd end up

$\displaystyle = \frac{16 - 16}{ \sqrt{16} - 4}$

$\displaystyle = \frac{0}{ 0}$

which isn't a good answer now notice that we have a square root on the denominator so we can rationalise the denominator to do so multiply the expression by √x+4/√x+4 which yields:

$\displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \times \frac{ \sqrt{x} + 4 }{ \sqrt{x} + 4 } \right)$