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Lunna [17]
3 years ago
15

PLEASE SOMEONE HELP ME. Use the given values to write a quadratic equation of the form f(x)=ax^2+bx+c:

Mathematics
1 answer:
Elden [556K]3 years ago
5 0

C)

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{vertex}{(2,-3)}~~ \begin{cases} h=2\\ k=-3 \end{cases}\implies y = a(x-2)^2-3 \\\\\\ \stackrel{passes~through}{(4,-1)}~~ \begin{cases} x=4\\ y=-1 \end{cases}\implies -1=a(4-2)^2-3\implies 2=a(4-2)^2 \\\\\\ 2=a(2)^2\implies 2=4a\implies \cfrac{2}{4}=a\implies \cfrac{1}{2}=a \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=\cfrac{1}{2}(x-2)^2-3~\hfill

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Step-by-step explanation:

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jasenka [17]

Answer:

Option D - x = 3 3/5

Step-by-step explanation:

Lets make the left side into an improper fraction :

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Now we substitute the equivalent values back into the equation :

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Now we multiply both sides by 15 to remove the denominators:

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