(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)
… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)
… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))
… = (2 - 2√3 <em>i</em> ) / 4
… = 1/2 - √3/2 <em>i</em>
… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))
… = exp(<em>i</em> arctan(-√3))
… = exp(-<em>i</em> arctan(√3))
… = exp(-<em>iπ</em>/3)
By DeMoivre's theorem,
[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1
Answer:10%
Step-by-step explanation:
Given:
27y and 54y³
To find:
The highest common factor (HCF) using prime factorization.
Solution:
We have,
27y and 54y³
Using the prime factorization, we get
Now, the common prime factors are 3, 3, 3 and y. So,
Therefore, the highest common factor of the given terms is 27y.
Answer:
Step-by-step explanation:
Given
Required
Simplify
To do this, we apply laws of indices:
So:
Add the exponents
Answer:
Answer is (1): 2 times (x^2 -13)
Step-by-step explanation:
Using the FOIL method, you can conclude that (x-5)(x+5) is X^2 -5x +5x -25. Since the two middle terms cancel, you are left with X^2 -25. For the right side of the equation, (x-1)(x+1), using the FOIL method gets you x^2 -x +x -1. Once again, the -x and x cancel out and you end up with X^2 -1. To add both of these together, you can get rid of all parentheses and do the work. Two x^2 added together is 2X^2, and -25-1 is negative 26. After this, you end up with 2x^2 -26. To get to your final answer you need to take out the GCF of both terms, (the largest number that can go into 2x^2 and -26), which is 2. Taking the two out leaves us with 2(x^2 -13), which is your final answer. It looks like you were on the right track.
FOIL Property
Multiply first terms
Then Outside terms
Then inside terms
Then the last terms
Hope this helps!