Question

Determine the specific heat of a metal that has a mass of 34.57 g that absorbs 678 J of heat and is heated from 25.0 °C to 55.0 °C.

Answer 1

Answer: $0.654 \text{ J/g} \cdot ^{\circ}\text{C}}$

Explanation:

$678=(34.57)(c)(55.0-25.0)\\\\c=\frac{678}{34.57(55.0-25.0)} \approx \boxed{0.654 \text{ J/g} \cdot ^{\circ}\text{C}}}$