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4 years ago

I NEED ANSWER PLEEEAASSEE!!!

2 answers:

3 0

The answer is B. This is because Sodium has 1 valence electron and Fluorine has 7 valence electrons. All elements want 8 valence electrons so they may be stale, like the noble gases are. Hope this helps.

vodka [1.7K]4 years ago

3 0

The answer to this question is B.

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HELP ASAP<br> Pleaseeee!!!!

kow [346]

Answer:

1 Second

Explanation:

10 meters per second for 10 meters, you just divide.

8 0

3 years ago

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the countercurrent arrangement of the two limbs of the loop of henle becomes a multiplier of electrolyte concentration due to wh

enot [183]

The counter-current is the process that occurs in the excretory system. The limbs become the multiplier because of the active transport of the electrolytes that move out.

<h3>What is the loop of Henle?</h3>

The loop of Henle is the part of the excretory system and part of the nephron. It functions in minimizing the water loss in the excretion of urine. There are descending and ascending loops present.

The ascending loop is impermeable to water but permeable to the electrolytes, and hence the concentration of the sodium, potassium, and chloride ions are actively pumped. This makes the solution more concentrated in the ascending loop.

Therefore, the electrolyte concentration results in active transport.

Learn more about the loop of Henle here:

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5 0

2 years ago

The change in frequency of a wave acceleration

nikdorinn [45]

Answer:

it decreases the amplitude of the wave as it propagates

Explanation:

5 0

3 years ago

Write in short adsorbent chromatography

Anna [14]

The adsorbent is the stationary phase in column chromatography and fills the glass column.

3 0

3 years ago

The following equations are half reactions and reduction potentials. Ag+ (aq) + e– Ag(s) has a reduction potential of +0.80 V. C

Lady bird [3.3K]

Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.

Explanation :

The given half reaction are :

1st half reaction : $Ag^+(aq)+e^-\rightarrow Ag(s)$

The reduction potential of this reaction = +0.80 V

2nd half reaction : $Cr^{3}+(aq)+3e^-\rightarrow Cr(s)$

The reduction potential of this reaction = -0.74 V

From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.

Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.

The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.

Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.

5 0

4 years ago

Read 2 more answers