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2 years ago

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A baseball is thrown into the air from a height of 5 feet. the ball reaches a maximum height of 43.5 feet and spends a total of

3.2 seconds in the air. which equation models the height of the baseball? assume that acceleration due to gravity is –16 ft/s2. h(t) = 16t2 49.64t 5 h(t) = -16t2 5t 49.64 h(t) = -16t2 49.64t 5 h(t) = 16t2 5t 49.64

1 answer:

KATRIN_1 [288]2 years ago

7 0

The equation that models the height of the baseball is determined as H(t) = 5 + 49.64t -16(t)².

<h3>Maximum height reached by the base ball</h3>

The maximum height reached by the baseball is calculated as follows;

H = y₀ + v₀yt + ¹/₂gt²

Assuming negative direction for upward motion

H = y₀ + v₀yt - ¹/₂gt²

0 = y₀ + vt -16(t)²

0 = 5 + 3.2v - 16(3.2)²

0 = 5 + 3.2v - 163.84

3.2v = 158.84

v = 158.84/3.2

v = 49.64

<h3>Required equation model</h3>

H(t) = 5 + 49.64t -16(t)²

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

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