Question

A baseball is thrown into the air from a height of 5 feet. the ball reaches a maximum height of 43.5 feet and spends a total of 3.2 seconds in the air. which equation models the height of the baseball? assume that acceleration due to gravity is –16 ft/s2. h(t) = 16t2 49.64t 5 h(t) = -16t2 5t 49.64 h(t) = -16t2 49.64t 5 h(t) = 16t2 5t 49.64

Answer 1

The equation that models the height of the baseball is determined as H(t) = 5 + 49.64t -16(t)².

Maximum height reached by the base ball

The maximum height reached by the baseball is calculated as follows;

H = y₀ + v₀yt + ¹/₂gt²

Assuming negative direction for upward motion

H = y₀ + v₀yt - ¹/₂gt²

0 = y₀ + vt -16(t)²

0 = 5 + 3.2v - 16(3.2)²

0 = 5 + 3.2v - 163.84

3.2v = 158.84

v = 158.84/3.2

v = 49.64

Required equation model

H(t) = 5 + 49.64t -16(t)²

Learn more about maximum height here: brainly.com/question/12446886

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