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IrinaVladis [17]
3 years ago
5

(3v^4 - 2) - (7v^4 + 6)

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

So firstly, you want to foil - (7v^4 + 6) [Think of the minus sign as -1]: 3v^4 - 2 - 7v^4 - 6

Next, combine like terms and your answer will be: -4v^4-8

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The length of a rectangular plot of land is 10 yards more than its width if the area of the land is 600 yd.² find the dimensions
Andrews [41]

Answer:

The dimension of the plot is 30 yd by 20 yd

Step-by-step explanation:

Given;

Area = 600 yd^2

Length = width + 10

l = w + 10 ......1

Area of a rectangular plot is;

Area A = length × width

A = l × w

Substituting equation 1;

A = (w+10) × w

A = w^2 + 10w

600 = w^2 + 10w

w^2 +10w -600 = 0

Solving the quadratic equation;

w = -30 or 20

cannot be negative

w = 20 yd

l = w+10 = 20+10 = 30yd

The dimension of the plot is 30 yd by 20 yd

6 0
3 years ago
3 (x + 1) - 5 = 3x - 2<br> has how many solutions?
marissa [1.9K]

Answer:

Zero Solutions

Step-by-step explanation:

3x+3-5=3x-2

3x-3x= -2+5

0= 3

0 does not equal 3, so zero solutions.

7 0
3 years ago
which statements are true for all rectangles A. All sides are equal in length B. All angles are right angles C. All angles are a
Elenna [48]

Answer:

I believe the correct answer is B.  

Step-by-step explanation:

4 0
3 years ago
PLS Help! What is the best approximation for the perimeter of a semicircle with a diameter of 12cm? Use 3.14 to approximation pi
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Answer:

A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.
ehidna [41]
1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
     i) bisect the angles so m(ODC)=60°/2=30°

     ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, DO= \sqrt{ DC^{2}- OC^{2} }=  \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}= 
=\sqrt{9}* \sqrt{3} =3\sqrt{3}  (in)

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}==2*9 \sqrt{3}=18 \sqrt{3} (in^{2})

6 0
3 years ago
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