Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm
step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm
step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm
step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm
step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD
step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and
AB and AD are perpendicular
BC and CD are perpendicular
therefore
the shape is a square wit length side √18 cm
area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²
the answer is18 cm²see the attached figure
Converting
<span>43°24' intodegrees, we get
</span>
43°24' = 43° + 24'/60 = 43.4°
putting <span> sin(43.4)</span>into calculator to 8 decimal places
sin(43°24') = sin(43.4) = 0.68708751
Answer:
Step-by-step explanation:
i don't take trig :/
Answer:
y = - 4x + 16
Step-by-step explanation:
Assuming you require the equation of the line passing through the points.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 4) and (x₂, y₂ ) = (5, - 4)
m =
=
= - 4, thus
y = - 4x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 4), then
4 = - 12 + c ⇒ c = 4 + 12 = 16
y = - 4x + 16 ← equation of line
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