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3 years ago

What is the expectation for a binomial distribution with p = 0.5 and n = 8?

Mathematics

1 answer:

Natasha2012 [34]3 years ago

8 0

Answer: 4

Step-by-step explanation:

Given the following :

P = probability of success = 0.5

n = number of trials = 8

The expected value of a binomial distribution with probability of success P and number of trials n is defined by:

E(n, p) = n * p

Therefore, expected value when P = 0.5 and n = 8

E(8, 0.5) = 8 × 0.5

= 4

The expected value of the binomial distribution is 4

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To find:

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Step-by-step explanation:

We have,

$5+4\times 2+6-2\times 2-1$

Now,

$(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1$

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And many more possibilities.

Therefore, the expression after inserting the parentheses is $(5+4)\times 2+6-2\times 2-1$ .

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