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mojhsa [17]
1 year ago
5

I need help with this page

Mathematics
1 answer:
arlik [135]1 year ago
6 0

Answer:

check image below

Step-by-step explanation:

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If 2x + 5 =8 ×, then 12x=
nadya68 [22]
<span>2x + 5 =8x
6x = 5
x = 5/6

12x = 12(5/6) = 10</span>
5 0
3 years ago
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Determine whether parallelogram JKLM with vertices J(-7, -2), K(0, 4), L(9, 2) and M(2, -4) is a rhombus, square, rectangle or a
White raven [17]
Check the picture below

now, we know is a parallelogram, so the diagonals will bisect

looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason

is it a rhombus?  well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal

now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;J&({{-7 }}\quad ,&{{ -2}})\quad &#10;%  (c,d)&#10;K&({{ 0}}\quad ,&{{ 4}})\\\\&#10;K&({{ 0}}\quad ,&{{ 4}})\quad &#10;%  (c,d)&#10;L&({{ 9}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;JK=\sqrt{[0-(-7)]^2+[4-(-2)]^2}\implies JK=\sqrt{(0+7)^2+(4+2)^2}&#10;\\\\\\&#10;JK=\sqrt{7^2+6^2}&#10;\\\\\\&#10;KL=\sqrt{(9-0)^2+(2-4)^2}\implies KL=\sqrt{9^2+(-2)^2}

now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL

and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;K&({{ 0}}\quad ,&{{ 4}})\quad &#10;%   (c,d)&#10;M&({{ 2}}\quad ,&{{ -4}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-4-4}{2-0}

\bf -------------------------------\\\\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;J&({{ -7}}\quad ,&{{ -2}})\quad &#10;%   (c,d)&#10;L&({{ 9}}\quad ,&{{ 2}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-(-2)}{9-(-7)}\implies \cfrac{2+2}{9+7}

then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.

7 0
3 years ago
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Solve for x then solve for b
trasher [3.6K]

Answer:

x= 6 and b= 126°

Step-by-step explanation:

okay the first step to solving this is understanding what are the properties of ∠A and ∠B.

so the angles are equal to each other because they are alternate interior angles.

if that is settled it means the equation for both angles would be equal to each other as well.

∠A= 8x + 78°  ∠B= 2x + 114°

therefore: 8x + 78= 2x + 114

                 then solve for x:

  • isolate x and the answer is equal to 6 at the end

now you are looking for angle b, so you input x which is 6 into the equation;

  • ∠B= 2x + 114°

    = 2(6) + 114°

    =12 + 114°

    =126°

3 0
3 years ago
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How many solutions does this nonlinear system of equaTions have?
RideAnS [48]

Answer:

There are five possible types of solutions to the system of nonlinear equations representing an ellipse and a circle

Step-by-step explanation:

P.S Can I have brainliest?

8 0
3 years ago
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I am thinking of a number, let's call it x . If I increase twice my number by 5, the result is the same as if I triple my number
Mrrafil [7]

Answer: 6

Step-by-step explanation:

Let the number be x

If I increase twice my number by 5, the result is the same as if I triple my number and subtract 1. This can be formed into an equation as:

(2 × x) + 5 = (3 × x) - 1

2x + 5 = 3x - 1

5 + 1 = 3x - 2x

x = 6

The number you are thinking of is 6

4 0
3 years ago
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