Question

Find the equation of the line shown. y 3 2 2 3 5 2 2 3 4 5

Answer 1

Answer: $y=\frac{1}{2}x+\frac{1}{2}$

Step-by-step explanation:

The line passes through (-1, 0) and (3,2), so the gradient is $\frac{2-0}{3-(-1)}=\frac{1}{2}$.

This means the equation of the line is of the form $y=\frac{1}{2}x+c$ for some constant c.

Substituting in the coordinates of the point (-1,0),

$0=\frac{1}{2}(-1)+c\\\\0=-\frac{1}{2}+c\\ \\ c=\frac{1}{2}$

Thus, the equation of the line is $y=\frac{1}{2}x+\frac{1}{2}$