This is C. cos Z = sin (90 - Y)
Answer:
x= -11;y= -19
Step-by-step explanation:
lets name y-2x=3 "A" ;
name 3x-2y=5 "B".
2A: 2y-4x=6
2A+B: (2y-4x)+(3x-2y)=6+5
2y-4x+3x-2y=11
-x=11
so x= -11
so A is : y-2 (-11)=3
y+22=3
so
y= -19
Answer:
There are 3 2/3 groups of 3/4 in 11/4
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Answer:
54 - 14 = 30
Step-by-step explanation:
