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Leto [7]
3 years ago
9

Help me pleaseeeeeeeeeeeee

Mathematics
2 answers:
Tanya [424]3 years ago
5 0
D Is You Answer! Vertical Asymptote
enyata [817]3 years ago
3 0
Your answer is D. Vertical Asymptote
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What is the rounding or compatible number<br><br> of 256+321
Nana76 [90]
<span>Compatible </span>numbers for 256...
1. Rounded to the nearest hundred = 200
2. Rounded to the nearest tens place = 260

Compatible numbers for 321...
1. Rounded to the nearest hundred = 300
2. Rounded to the nearest tens place = 320

I hope this helps! :)


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Can someone help me answer this please
Black_prince [1.1K]

Answer:

(x-2)^2 +(y+3)^2 = 16

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