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uranmaximum [27]
2 years ago
9

It was experimentally determined from three trials that an object had a density of 0.96, 0.99, and 0.95 g/mL. What is the averag

e density and standard deviation of this object
Chemistry
1 answer:
Travka [436]2 years ago
3 0

The mean of the sample is 0.97 while the standard deviation of the sample is 0.015.

<h3 /><h3>What is the average density?</h3>

The average density is the sum of the density values divided by the total number of measurements.

In this case, we have three trials, the mean of the samples is 0.96 + 0.99 +0.95/3 = 0.97

The standard deviation is obtained from;

s= \sqrt{(0.96 - 0.97)^2 + (0.99 - 0.97)^2 + (0.95 - 0.97)^2/(3 - 1)}

s = \sqrt{(0.0001) + (0.0004) + (0.0004)/2}

s = 0.015

Learn more about standard deviation:brainly.com/question/16555520

#SPJ4

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The vapor pressure of liquid pentane, C5H12, is 40.0 mm Hg at 244 K. A sample of C5H12 is placed in a closed, evacuated containe
Rudik [331]

Answer:

b. The pressure in the container will be 100mm Hg.

d. Some of vapor initially present will condense.

Explanation:

The vapor pressure of liquid Pantene rises when there is container where evacuation of water molecules is restricted. The pressure inside the container rises to 100 mm Hg and then liquid molecules start condensing. These molecule form vapors.

5 0
3 years ago
If the volume of a solid is 100 cm3 and its mass is 400 g, what is its density?
Dafna1 [17]
Under these circumstances, Its density is 4 grams per cm3
5 0
4 years ago
Q8. The titration of 15.00 mL of HBr solution of unknown concentration requires 18.44 mL of a 0.100 M KOH solution to reach the
lara [203]

Answer: 0.123 M

Explanation:

According to the neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HBr solution = ?

V_1 = volume of HBr solution = 15.00 ml

M_2 = molarity of KOH solution = 0.100 M

V_2 = volume of KOH solution = 18.44 ml

n_1 = valency of HBr = 1

n_2 = valency of KOH = 1

1\times M_1\times 15.00=1\times 0.100\times 18.44

M_1=0.123

Therefore, the concentration of the unknown HBr solution is 0.123 M

8 0
3 years ago
How many atoms are contained in 100.0 g of mercury
Romashka [77]

3.00097 x 10^{23} atoms are contained in 100.0 g of mercury.

<h3>What is moles?</h3>

The mole is defined as the amount of substance that contains as many elementary entities as there are atoms in exactly 12 g of carbon-12.”

Number of moles of mercury = \frac{mass}{molar \;mass}

Number of moles of mercury = \frac{100.0 g}{200.59 u}

=  0.4985 moles

Number of moles of mercury = Number of atoms = moles of Hg x 6.02 X 10^{23}

= 0.4985 x 6.02 X 10^{23}

= 3.00097 x 10^{23} atoms.

Hence, 3.00097 x 10^{23} atoms are contained in 100.0 g of mercury.

Learn more about the moles here:

brainly.com/question/26416088

#SPJ1

5 0
2 years ago
Which of these is given away or accepted by an atom when it reacts with other atoms?
Alborosie
A; Electron is your answer.
7 0
3 years ago
Read 2 more answers
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