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Zigmanuir [339]
4 years ago
5

How many carbon atoms are in four molecules of glucose, or 4c6h12o6?

Chemistry
2 answers:
Mandarinka [93]4 years ago
4 0
One can find there are 6 carbon atoms<span>, 12 hydrogen atoms and 6 oxygen atoms in one molecule of glucose. Hope this helps :) Have a great day :) Remember to always be positive :) </span>
Kruka [31]4 years ago
3 0

Answer: 12 carbon atoms

Explanation:

Atom is the smallest unit of matter which may or may not have independent existence. Example: N

Molecule is the smallest unit of matter which has a independent existence.Example: N_2

1 molecule of C_6H_{12}O_6 has 6 atoms of carbon

Thus if 1 molecule of C_6H_{12}O_6 has carbon atoms = 3

4 molecules of C_6H_{12}O_6 has total of =\frac{3}{1}\times 4=12atoms

Thus there are 12 carbon atoms in four molecules of glucose.

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Lila is a track and field athlete. She must complete four laps around a circular track. The track itself measures 400 meters fro
Aleks [24]

Answer:

its D Her speed is 4.4 m/s, and her velocity is 4.4 m/s.

Explanation:

i took the quiz

5 0
3 years ago
When two or more refrigerants are mixed, what must be done with the mixture?
Lana71 [14]
<span>When refrigerants are mixed, somebody must recover the mixture into a separate </span><span>container or tank.
</span>Refrigerant<span> is a mixture,</span> that can transform from liquid to gas and vice versa. Refrigerants <span>used in a </span>heat pump and refrigerators. They <span>should not be mixed together, one of the reason is because they are flammable.</span>
5 0
3 years ago
Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:
Temka [501]

The question is incomplete , complete question is:

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:

(a) n = 2 to n = 4

(b) n = 2 to n = 1

(c) n = 2 to n = 5

(d) n = 4 to n = 3

Answer:

Hence the order of the transition will be : d < a < c < b

Explanation:

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6 eV

Energy of n = 2 in an hydrogen atom:

E_2=-13.6\times \frac{1^2}{2^2}eV=-3.40eV

Energy of n = 3 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy of n = 4 in an hydrogen atom:

E_4=-13.6\times \frac{1^2}{4^2}eV=-0.85 eV

Energy of n = 5 in an hydrogen atom:

E_5=-13.6\times \frac{1^2}{5^2}eV=-0.544 eV

a) n = 2 to n = 4 (absorption)

\Delta E_1= E_4-E_2=-0.85eV-(-3.40eV)=2.55 eV

b) n = 2 to n = 1 (emission)

\Delta E_2= E_1-E_2=-13.6 eV-(-3.40eV)=-10.2 eV

Negative sign indicates that emission will take place.

c) n = 2 to n = 5 (absorption)

\Delta E_3= E_5-E_2=-0.544 eV-(-3.40eV)=2.856 eV

d) n = 4 to n = 3 (emission)

\Delta E_4= E_3-E_4=-1.51 eV-(-0.85 eV)=-0.66 eV

Negative sign indicates that emission will take place.

According to Planck's equation, higher the frequency of the wave higher will be the energy:

E=h\nu

h = Planck's constant

\nu frequency of the wave

So, the increasing order of magnitude of the energy difference :

E_4

And so will be the increasing order of the frequency of the of the photon absorbed or emitted. Hence the order of the transition will be :

: d < a < c < b

7 0
4 years ago
The density of the solid phase of a substance is 0.90 g/cm3 and the density of the liquid phase is 1.0 g/cm3. A large increase i
aliina [53]

Answer:

it is c

Explanation:

5 0
4 years ago
Read 2 more answers
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
sukhopar [10]

Answer:

1.5

Explanation:

Given that :

Compound A and B are formed from Sulfur + Oxygen.

Compound A :

6g sulfur + 5.99g Oxygen

Compound B:

8.6g sulfur + 12.88g oxygen

Comparing the ratios :

Compound A:

S : O = 6.00 : 5.99

S/0 = 6.0g S / 5.99g O

Compound B :

S : O = 8.60 : 12.88

S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

4 0
4 years ago
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