How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?

Which diagram shows how the particles of the solid substance will look after it has absorbed enough heat to melt partially ??

cricket20 [7]

It would be A, the molecules should be closely packed together but arranged randomly. :)

4 0

3 years ago

Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili

Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

$\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}$

$\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M$

$\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M$

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

$H_2+I_2\rightleftharpoons 2HI$

<u>Initial:</u> 0.1 0.1

<u>At eqllm:</u> 0.1-x 0.1-x 2x

Evaluating the value of 'x'

$\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

$[HI]_{eq}=2x=(2\times 0.079)=0.158M$

$[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M$

$[I_2]_{eq}=0.0210M$

Putting values in above expression, we get:

$K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61$

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

A local plant nursery uses large sprinklers to water the plants twice a day. the water contains phosphorus, which is a fertilize

Mumz [18]

Eutrophication

In an aged aquatic habitat like a lake, eutrophication is the progressive rise in the concentration of phosphorus, nitrogen, and other plant nutrients. As the volume of organic matter that can be converted into nutrients increases, the productivity or fertility of such an ecosystem also naturally rises.

<h3>What is Eutrophication ?</h3>

Eutrophication may be caused by a number of things, including overuse of fertilisers, untreated sewage, the use of phosphorous-containing detergents, and industrial waste discharge.

Eutrophication naturally. Natural eutrophication is a process that develops in water resources over a very long period of time as a result of a slow buildup of nutrients and organic waste. Anthropogenic or cultural eutrophication.

Learn more about Eutrophication here:

brainly.com/question/26956972

#SPJ4

3 0

1 year ago

2. What is the mass of 16.3 L of helium gas?

lilavasa [31]

(16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g

3 0

3 years ago

Read 2 more answers

How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?​

How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?