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Soloha48 [4]
2 years ago
14

Find the measure of the angle labeled x (ADB) in the circle below. A B​

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0
The answer is the last option!
17’
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A circular pool is surrounded by a circular walkway. The radius of the pool is y − 4 and the radius of the full circle formed by
TiliK225 [7]
A=πr²

pool=π(y-4)²=π(y²-8y+16)
total=π(y+4)²=π(y²+8y+16)

walkway=total-pool
walkway=π(y²+8y+16)-π(y²-8y+16)=
π(y²+8y+16-y²+8y-16)=
π(16y)=
16πy
first option is answer
6 0
3 years ago
Rewrite the problem so that the divisor is a whole number
sveticcg [70]

8.76÷0.535=8760÷535

≈16.37

5 0
2 years ago
A construction crew is lengthening a road. Let L be the total length of the road (in miles). Let D be the number of days the cre
djverab [1.8K]

Answer:

Set of Values for Domain = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80}

Set of Values for Range = {402, 404, 406, 408, 410, 412, 414, 416, 418, 420, 422, 424, 426, 428, 430, 432, 434, 436, 438, 440, 442, 444, 446, 448, 450, 452, 454, 456, 458, 460, 462, 464, 466, 468, 470, 472, 474, 476, 478, 480, 482, 484, 486, 488, 490, 492, 494, 496, 498, 500, 502, 504, 506, 508, 510, 512, 514, 516, 518, 520, 522, 524, 526, 528, 530, 532, 534, 536, 538, 540 542, 544, 546, 548 550, 552, 554, 556, 558, 560}.

Step-by-step explanation:

Solution...

Assume that there is a link for the road between your house and the market the road maintenance team is meant to repair the road.

now the system of work is that the length of the road they will work upon is equal to 2 times the amount of days + 400.

This is to say that originally there is 400 miles of the road, and once they work in a day they add 2 more miles to the original 400. if they work in 2 days they add 4 more miles to the original 400. If they work in 3 days they add 6 more miles to the original 400.

So L = 2(D) + 400.

Answer 1.

description of the values in both the domain and range of a function.

the domain is the set of all values for which the function is defined.

this means that the domain is all numbers between 0 to 80.

Why do we begin from 0, because when you put 0 into the equation you have, L = 2(0) + 400, and this is equal to 2 x 0 + 400 or 400 + 0 (since all numbers multiplied by 0 gives 0).

Why is 80 the maximum, this is because they work for at most 80 days.

So the domain is

D = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80}

And the range is the set of all values that L (which is the function) takes, to get this you have to calculate the days from day 0 to day 80.

The range for the function is...

L = {402, 404, 406, 408, 410, 412, 414, 416, 418, 420, 422, 424, 426, 428, 430, 432, 434, 436, 438, 440, 442, 444, 446, 448, 450, 452, 454, 456, 458, 460, 462, 464, 466, 468, 470, 472, 474, 476, 478, 480, 482, 484, 486, 488, 490, 492, 494, 496, 498, 500, 502, 504, 506, 508, 510, 512, 514, 516, 518, 520, 522, 524, 526, 528, 530, 532, 534, 536, 538, 540 542, 544, 546, 548 550, 552, 554, 556, 558, 560}.

So how did we get all these. Using the figures registered as D to get the L.

Before solving, remember that, (HD is H•D or H × D,

2D is 2•D or 2 × D,

29F is 29•F or 29 × F... When numbers are used to multiply letters which stand as a varying value like X, Y, D etc, then they are written as 2x or 2•x or 2(x). They all mean multiply 2 by x)

So, i.e.

L = 2(D) + 400.

When it's day 1, D is 1

L = 2(1) + 400 which equals 2 + 400 = 402. So for 1 day, the crew has worked 402 miles.

On Day 2, D is 2

L = 2(2) + 400 which equals 4 + 400 = 404. So for 2 days, the crew has worked 404 miles.

On Day 3, D is 3

L = 2(3) + 400 which equals 6 + 400 = 406. So for 3 days, the crew has worked 406 miles.

On Day 4, D is 4

L = 2(4) + 400 which equals 8 + 400 = 408. So for 4 days, the crew has worked 408 miles.

On Day 5, D is 5

L = 2(5) + 400 which equals 10 + 400 = 410. So for 5 days, the crew has worked 410 miles.

On Day 6, D is 6

L = 2(6) + 400 which equals 12 + 400 = 412. So for 6 days, the crew has worked 412 miles.

...

...

...

For 7 days, the crew has worked 414 miles.

For 8 days, the crew has worked 416 miles.

For 9 days, the crew has worked 418 miles.

For 10 days, the crew has worked 420 miles.

For 20 days, the crew has worked 440 miles.

For 30 days, the crew has worked 460 miles.

For 40 days, the crew has worked 480 miles.

For 50 days, the crew has worked 500 miles.

For 60 days, the crew has worked 520 miles.

For 70 days, the crew has worked 540 miles.

For 75 days, the crew has worked 550 miles.

...

...

...

On Day 79, D is 79

L = 2(79) + 400 which equals 158 + 400 = 558. So for 79 days, the crew has worked 558 miles..

On Day 80, D is 80

L = 2(80) + 400 which equals 160 + 400 = 560. So for 80 days, the crew has worked 560 miles.

That is how the domain and range is determined.

6 0
3 years ago
Based on historical data, your manager believes that 41% of the company's orders come from first-time customers. A random sample
TEA [102]

Answer:

The probability that the sample proportion is between 0.35 and 0.5 is 0.7895

Step-by-step explanation:

To calculate the probability that the sample proportion is between 0.35 and 0.5 we need to know the z-scores of the sample proportions 0.35 and 0.5.

z-score of the sample proportion is calculated as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of first time customers
  • p is the proportion of first time customers based on historical data
  • N is the sample size

For the sample proportion 0.35:

z(0.35)=\frac{0,35-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ -1.035

For the sample proportion 0.5:

z(0.5)=\frac{0,5-0.41}{\sqrt{\frac{0.41*0.59}{72} } } ≈ 1.553

The probabilities for z of being smaller than these z-scores are:

P(z<z(0.35))= 0.1503

P(z<z(0.5))= 0.9398

Then the probability that the sample proportion is between 0.35 and 0.5 is

P(z(0.35)<z<z(0.5))= 0.9398 - 0.1503 =0.7895

6 0
3 years ago
Emma is playing miniature golf. Her ball is 2 feet to the left of the right-hand wall. The hole is 4 feet to the left of the wal
NISA [10]

Answer:

<u></u>

  • <u>She should aim 6 feet down the wall</u>

Explanation:

The diagram attached sketches the situtation.

Since the angle with which the ball hits the wall is the same with which it bounces, angle β is the same for the two shown triangles.

Then, since both are right triangles, then all the angles are congruent and the triangles are similar. Hence, you can equal the ratios of the sides, to make an equation:

  • x/4 = y/2 ⇒ x = 2y

You have other equation:

  • x+ y = 18

Substitute

  • 2y + y = 18
  • 3y = 18
  • y = 18/3
  • y = 6 ← this is the distance down the wall where the ball should hit

  • x = 2(6) = 12

Then, she should aim 6 feet down the wall.

8 0
3 years ago
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