Answer:A)The conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%
Step-by-step explanation:
In a two way frequency table, conditional relative frequency is it’s a fraction that tells us how many elements of of a group have a certain characteristic.
Here In a study about the relationship between marital status and job level, 8,235 males at a large manufacturing firm reported their job grade (from 1 to 4, with 4 being the highest) and their marital status.
from the given two way frequency table,
Number of widowed employees at grade 1 =8
Number of widowed employees at grade 2=20
∴ Number of widowed employees at grade 2 or below=8+20=28
And the total widowed employees working =42
Now the conditional relative frequency among widowed employees of those widowed working at grade 2 or below=
Therefore, the conditional relative frequency among widowed employees of those widowed working at grade 2 or below= 28/42 = 66.67%
Answer:
Δ SHD ≅ Δ STD (By SAS)
Step-by-step explanation:
Given:
SD⊥HT
SH=ST
Prove:
Δ SHD ≅ Δ STD
Computation:
SH=ST (Given)
SD = SD (Common)
∠SHD = ∠SDT (right angle) (SD⊥HT)
So,
Δ SHD ≅ Δ STD (By SAS)
Answer:
67.5
Step-by-step explanation:
Take the amount that you deposited and multiply it by the interest rate. Then would multiply it by 3 cause its 3 years that you would be getting that interest.
900 * 0.025 = 22.5
22.5 * 3 = 67.5
Answer:
c: 8 i'm sure
Step-by-step explanation:
Because we count where the line stops is 8 squares which means it's 8