Answer:
1
Step-by-step explanation:
any number that is raised to the zero power will equal to 1. hope this helps!
Ok so 8:12 can be 8 to 12, or 8\12
do that help?
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
8(1/4x + 3/4) -3 =17
First distribute which results in (8/4x + 24/4)-3 =17.
Now just simply simplify it into (2x+6)-3 =17
Then you combine like term : 2x+3 =17
Subtract 3 on both sides : 2x=14
Finally divide 2 on both sides to isolate x: x=7
Answer:
5.65+3.07=8.72
8.72/16=0.545
Each bag of gapes weight 0.545 pounds.
Step-by-step explanation:
