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2 years ago

11

HELP !!!

1 answer:

Dmitrij [34]2 years ago

5 0

The answer to this is negative

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There are 5280 feet in a mile. what fraction of a mile is represented by 660 feet?

alina1380 [7]

900/5280 = 90/528 = 45/264 = 15/88

CHECK: 15/88 * 5280 = 900

The answer to your question is = 15/88

HOPE THIS HELPS !!!!

7 0

4 years ago

A school is building a circular sandbox. The sandbox will have a diameter of 12

igor_vitrenko [27]

The correct answer is 37.7 sorry for the late response D;

3 0

3 years ago

Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a

Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

The area is given as:

$\mathbf{A = 1000}$

Let the dimension be x and y.

So, we have:

$\mathbf{A = xy = 1000}$

Make x the subject

$\mathbf{x = \frac{1000}{y}}$

The perimeter is calculated as:

$\mathbf{P = 2(x + y)}$

Substitute $\mathbf{x = \frac{1000}{y}}$

$\mathbf{P = 2(\frac{1000}{y} + y)}$

Expand

$\mathbf{P = \frac{2000}{y} + 2y}$

Differentiate

$\mathbf{P' = -\frac{2000}{y^2} + 2}$

Set to 0

$\mathbf{ -\frac{2000}{y^2} + 2 = 0}$

Rewrite as:

$\mathbf{ -\frac{2000}{y^2} = -2}$

Divide both sides by -1

$\mathbf{\frac{2000}{y^2} = 2}$

Multiply y^2

$\mathbf{2000 = 2y^2}$

Divide by 2

$\mathbf{1000 = y^2}$

Take square roots of both sides

$\mathbf{y = \sqrt{1000 }}$

$\mathbf{y = 10\sqrt{10 }}$

Substitute $\mathbf{y = \sqrt{1000 }}$ in $\mathbf{x = \frac{1000}{y}}$

$\mathbf{x = \frac{1000}{\sqrt{1000}}}$

$\mathbf{x = \sqrt{1000}}$

$\mathbf{x = 10\sqrt{10 }}$

Hence, the dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

Read more about perimeters at:

brainly.com/question/6465134

8 0

3 years ago

42,000 as a multipul of a power of 10

MrRa [10]

Answer:

$4.2 \times {10}^{4}$

Step-by-step explanation:

$42000 = 4.2000 \times \times {10}^{4} \\ = 4.2 \times {10}^{4}$

3 0

3 years ago

What is the volume of this pyramid

irga5000 [103]

Check the picture below.

$\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{\textit{triangular base}}{\frac{1}{2}(14)(18)}\\[1em] h=30 \end{cases}\implies V=\cfrac{1}{3}\left( \cfrac{1}{2}(14)(18) \right)(30) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V=1260~\hfill$

3 0

3 years ago