1 year ago

HELP !!!

Mathematics

1 answer:

Dmitrij [34]1 year ago

5 0

The answer to this is negative

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The Vice President Of Sales Took A Client Out To Lunch. If The Lunch Was $44 And She Gave A 20% Tip, How Much Money Did She Spen

Ray Of Light [21]

The answer is 52.80 because the tip is $8.80 and 44.00+8.80=52.80

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3 years ago

Please help with this question and show work

alukav5142 [94]

The diagonals of a parallelogram bisect each other so
4x - 7 = x + 2 and
5y - 8 = 3y

4x - 7 = x + 2 so 3x = 9 and x = 3

5y - 8 = 3y so 2y = 8 and y = 4

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2 years ago

jasmine took a cab home from her office. the cab charged a flat fee of $4, plus $2 per mile. Jasmine paid $32 for the trip. How

kykrilka [37]

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3 years ago

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Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

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3 years ago

Distributive Property<br> 1/4(12 – 4t)

Alex777 [14]

Answer: 3-t
1. 1/4(12)+1/4(-4t)
2.3-t

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2 years ago

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