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Tasya [4]
2 years ago
8

haru rides his bike from his home for 30 minutes at a fast pace. He stops to rest for 20 minutes, and then continues riding in t

he same direction at a slower pace for 30 more minutes. Sketch a graph of the relationship of Haru’s distance from home over time.
Mathematics
1 answer:
Bezzdna [24]2 years ago
6 0

Using the given information and what we know about linear equations, we will find the sketch below.

<h3>How to sketch a graph?</h3>

Here we need to analyze each part separately.

In a coordinate axis where the y-axis represents distance and the x-axis represents time, we will have that:

First, we know that he rides for 30 minutes at a given speed, this will be represented with an increasing linear function.

Then he stops for 20 minutes, this is represented with a horizontal line.

Finally, he returns the motion, but slower than before, so the slope of this line will be smaller than the first one.

So for 0 to 30 we have an increasing linear equation, then for 30 to 50 we have a constant horizontal line, then for 50 to 80 we have another increasing linear equation

The sketch can be seen below.

If you want to learn more about linear equations, you can read:

brainly.com/question/4074386

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Answer:

(a)The total number of outcomes where the sum is 9 or

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(b)Total number of outcomes where the sum is odd = 18

(c)Total number of outcomes where the  sum greater or equal to 9 and is

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Step-by-step explanation:

Here, Sample Space = { Sum of the two digits when two dices are thrown together}

or,   S   =   {2,3,4,5,6,7,8,9,10,11,12}

(a)  The number of ordered pairs where sum is  9 or greater than 9

    = { sum is 9  ,  Sum is 10 ,  Sum is 11,   Sum is 12}

    = {(6,3)(3,6),(4,5)(5,4) ,   (5,5), (6,4),(4,6)  , (6,5)(5,6),   (6,6)}

Hence the total number of outcomes where the sum is 9 or

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(b)  The number of ordered pairs where sum is odd.

    = { Sum is 3 ,  Sum is 5,   Sum is 7, Sum is 9, Sum is 11}

    = {(1,2)(2,1),   (4,1)(1,4),(2,3)(3,2) ,   (6,1), (1,6),(5,2),(2,5),(4,3)(3,4)  ,

        (6,3)(3,6), (4,5)(5,4),  (6,5),(5,6)}  = 18

Hence total number of outcomes where the sum is odd = 18

(c) Intersection point refers the outcomes which have sum greater or equal to 9 and is odd

Here, the possible outcomes are  = { Sum is 9 ,  Sum is 11}

                                            ={ (6,3)(3,6), (4,5)(5,4),  (6,5),(5,6)}  = 6

Hence total number of outcomes where the  sum greater or equal to 9 and is also odd = 6

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