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3 years ago

8

9. Pentagon ASDFG is translated 4 units to the right and 5 units down to make pentagon A'S'D'F'G'. Which rule

1 answer:

Ludmilka [50]3 years ago

6 0

B is the answer to the question

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On the average, a certain light bulb is supposed to last 450 hours. If it

Dafna1 [17]

Answer:

72 novels

Step-by-step explanation:

A number of assumptions are involved regarding operating environment, utilization fraction, and probability of failure as a function of time. The precise meanings of the words "average", "supposed to last", "maximum", and "expect" are involved. The details are too arcane to go into here.

(450 hours)/(6 1/4 hours/novel)

= (450/(25/4)) novels

= (450*4/25) novels

= 72 novels

6 0

3 years ago

How to solve (2y+8)/(16+4y)

Hitman42 [59]

<span>(2y+8)/(16+4y)

2(y + 4)
= ---------------
4(y + 4)

= 1/2
answer
1/2</span>

4 0

3 years ago

Which two equations are parallel?

Mekhanik [1.2K]

Answer: The third option is correct.

Step-by-step explanation:

In order for two equations to be parallel, the equations' slopes must be the same.

5 0

2 years ago

Pre-Calculus - Systems of Equations with 3 Variables please show work/steps

Tatiana [17]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0

3 years ago

Find the diagonal of the rectangular prism to the nearest tenth.<br> 4 in<br> 3 in<br> 10 in

hoa [83]

Given:

Consider the dimensions of a rectangular prism are 4 in by 3 in by 10 in.

To find:

The length of the diagonal.

Solution:

Length of diagonal of a rectangular prism is:

$d=\sqrt{l^2+b^2+h^2}$

Where l is length, b is breadth and h is height.

The dimensions of a rectangular prism are 4 in by 3 in by 10 in. So, the length of diagonal of the rectangular prism is:

$d=\sqrt{(4)^2+(3)^2+(10)^2}$

$d=\sqrt{16+9+100}$

$d=\sqrt{125}$

$d=5\sqrt{5}$

Approximate the value to the nearest tenth.

$d\approx 11.2$

Therefore, the length of diagonal of the rectangular prism is 11.2 in.

5 0

3 years ago