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MakcuM [25]
1 year ago
12

5^4/5^7 simplified is

Mathematics
2 answers:
Nuetrik [128]1 year ago
5 0

\textbf{Given that,}\\\\~~~\dfrac{5^4}{5^7}\\\\\\=5^{4-7}~~~~~~~~~~~~~~~~~~~~~~~~;\textbf{Apply exponent rule:}~\dfrac{a^m}{a^n} = a^{m-n}\\\\\\=5^{-3}\\\\\\=\dfrac 1{5^3}~~~~~~~~~~~~~~~~~~~~~~~~~~;\textbf{Apply exponent rule:}~ a^{-n} = \dfrac 1 {a^n},~~~a \neq 0 \\\\\\=\dfrac 1{125}\\\\\\=0.008

Zielflug [23.3K]1 year ago
5 0

Answer:

\frac{1}{125}

Step-by-step explanation:

1.apply \: exponent \: rules :   \frac{ {x}^{a} }{ {x}^{b} }  =   {x}^{a - b}

=  {5}^{4 - 7}

2.subtract \: the \: number : 4 - 7 =  - 3

=  {5}^{ - 3}

3.apply \: exponent \: rule :  {a}^{ - b}  =  \frac{1}{  {a}^{b}  }

=  \frac{1}{ {5}^{3} }

4. \:  {5}^{3}  = 125

=  \frac{1}{125}

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| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

3 0
2 years ago
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