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zaharov [31]
2 years ago
5

Вхід на станцію метрополітену обладнаний системою к=4 турнікетів. При виході з ладу одного з турнікетів решта продовжують нормал

ьно функціонувати. Вхід на станцію перекривається, якщо вийдуть з ладу всі турнікети. Потік відмовлень кожного турнікету - найпростіший, середній час безвідмовної роботи одного турнікету 175 годин. При виході з ладу кожний турнікет починає відразу ремонтуватися. Час ремонту розподілено за показниковим законом і в середньому складає 5-3 годин. В початковий момент всі турнікети справні. Знайти середню пропускну спроможність системи турнікетів у відсотках від номінальної, якщо з виходом з ладу кожного турнікету система втрачає (100/k) % своєї номінальної пропускної спроможності
Mathematics
1 answer:
Harman [31]2 years ago
6 0
:/……………i don’t know what you just said
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You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in
jeka57 [31]

Answer:

You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, <em>r</em> = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, <em>c</em> = 3.

The distribution of the statistic \chi^{2} is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.

Compute the degrees of freedom as follows:

df = (r-1)(c-1)=(2-1) \times (3-1) = 2

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the <em>p</em>-value of the test as follows:

p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011

Decision rule:

The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.

The significance level is, <em>α</em> = 0.05.

<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."

4 0
3 years ago
F(9) if f (x)=5x-16
andrezito [222]
F (9)= 5(9) -16
45-16
f(9)=29
8 0
3 years ago
If g(x) =3/2 x +4, what is the value of g(2)?
Otrada [13]

Answer:

7

Step-by-step explanation:

g(x) = 3/2 x + 4

g(2) = 3/2 * 2 + 4

g(2) = 3 +4

g(2) = 7

8 0
3 years ago
A card is selected randomly from a jar that contains 15 cards, numbered from 25 to 39. What is the probability that the card sel
VikaD [51]

Answer:

The probability that the card selected bears a number less than 34 is 0.3333.

Step-by-step explanation:

Let random variable <em>X</em> be defined as the number on the selected card.

There are <em>N</em> = 15 total cards.

The number on the cards are as follows:

S = {25, 26, 27,..., 38, 39}

The probability of an event, <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

In this case we need to compute the probability that the card selected bears a number less than 34.

The favorable outcomes are:

<em>s</em> = {25, 36, 37, 38, 39}

<em>n</em> (X < 34) = 5

Compute the probability that the card selected bears a number less than 34 as follows:

P(X

                  =\frac{5}{15}\\\\=\frac{1}{3}\\\\=0.3333

Thus, the probability that the card selected bears a number less than 34 is 0.3333.

7 0
3 years ago
.William sold half of his comic book collection and then purchased 10 more . He now has 24 comic books period how many books did
Assoli18 [71]

Answer:

28 books

Step-by-step explanation:

Let x represent the number of books .William owned before anything happens

x/2 + 10 = 24

2(x/2 + 10) = 2(24)

x + 20 = 48

x = 48 - 20

x = 28

8 0
3 years ago
Read 2 more answers
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