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zaharov [31]
1 year ago
5

Вхід на станцію метрополітену обладнаний системою к=4 турнікетів. При виході з ладу одного з турнікетів решта продовжують нормал

ьно функціонувати. Вхід на станцію перекривається, якщо вийдуть з ладу всі турнікети. Потік відмовлень кожного турнікету - найпростіший, середній час безвідмовної роботи одного турнікету 175 годин. При виході з ладу кожний турнікет починає відразу ремонтуватися. Час ремонту розподілено за показниковим законом і в середньому складає 5-3 годин. В початковий момент всі турнікети справні. Знайти середню пропускну спроможність системи турнікетів у відсотках від номінальної, якщо з виходом з ладу кожного турнікету система втрачає (100/k) % своєї номінальної пропускної спроможності
Mathematics
1 answer:
Harman [31]1 year ago
6 0
:/……………i don’t know what you just said
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t = 1 year

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Pls find the blank space. <br><br>the first answer will get marked brainliest​
True [87]

Step 1

Anything divided by one gives itself.

\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}

8

1

=−8 and

1

−8

=

48

−12

Step 2

Convert -8−8 to fraction -\frac{64}{8}−

8

64

.

\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}

8

1

=−

8

64

and

1

−8

=

48

−12

Step 3

Compare \frac{1}{8}

8

1

and -\frac{64}{8}−

8

64

.

\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and

1

−8

=

48

−12

Step 4

Anything divided by one gives itself.

\text{false}\text{ and }-8=\frac{-12}{48}false and −8=

48

−12

Step 5

Reduce the fraction \frac{-12}{48}

48

−12

to lowest terms by extracting and canceling out 1212.

\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−

4

1

Step 6

Convert -8−8 to fraction -\frac{32}{4}−

4

32

.

\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −

4

32

=−

4

1

Step 7

Compare -\frac{32}{4}−

4

32

and -\frac{1}{4}−

4

1

.

\text{false}\text{ and }\text{false}false and false

Step 8

The conjunction of \text{false}false and \text{false}false is \text{false}false.

\text{false}false

Hint

Do the arithmetic.

Solution

\text{false}false

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2 years ago
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