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Pie
3 years ago
14

5d=10d-20 please answer quickly

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
4 0

Answer:

D = 4

Step-by-step explanation:

None

Varvara68 [4.7K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Subtract 10d from both sides

5d-10d=-5d

-5d=-20

d=4

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Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
romanna [79]

Answer:

11x+y = -28

Step-by-step explanation:

We have two points so we can find the slope

m = (y2-y2)/(x2-x1)

   = (-6-5)/ (-2--3)

   = -11(-2+3)

   = -11/1

The slope is -11

We can use point slope to make an equation

y-y1 = m (x-x1)

y-5 = -11(x--3)

y -5 = -11(x+3)

Distribute

y-5 = -11x-33

Add 5 to each side

y-5+5 = -11x-33+5

y = -11x-28

Add 11x to each side

11x+y = -11x+11x-28

11x+y = -28

This is the standard form of a line

5 0
3 years ago
Graph<br>f(x) = 3 |x| + 9
Anastaziya [24]

Answer:

see graph

Step-by-step explanation:

to find points on the graph, enter in x values and find y.

3|-4|+9 =  21  (-4, 21)

3|2|+9 = 15  (2, 15

6 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
A driver drove for 3 hours at a certain speed. If he drove 12 more miles at the same speed, the distance would be 132 miles. At
Zinaida [17]
Distance traveled in 3 hrs was (speed in mph)(3 hrs)

Then s(3 hrs) + 12 mi = 132 mi.

Therefore, 3s = 120, and s = 120 miles   /   3 hrs   = 40 mph (answer)
7 0
3 years ago
What is the surface area of a cylinder with base radius 4 and height 5
mestny [16]
A=226.19 A=2πrh+2πr2=2·π·4·5+2·π·42≈226.19467
7 0
3 years ago
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