3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
.................................................
1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25
the answer is D
the square root of 6 because it cannot be written as a fraction
Answer: 196 :)
Step-by-step explanation:
Answer:
Yes, in order to solve equations make sure to collect terms together - usually this makes the problem a lot easier to solve!
So subtract 5x from both sides to get
3 = 5x - 2
add 2 to both sides to get
5x = 5
now divide both sides by 5 to get
x = 1
