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2 years ago

7

A rope was 14.35 inches long. Megean cut the rope into 7 pieces of equal length. What was the length of each piece of rope in in

ches
PLSS HELP!!!

1 answer:

kondor19780726 [428]2 years ago

4 0

Answer: 2.05 inches

Reason:

Divide the two values to get (14.35)/(7) = 2.05

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2(x-3)-12 = -4<br> How do I solve this equations

deff fn [24]

Answer:

x= 7

Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12 (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

5th step: since 2 is being multiplied by x, when you send it to the other side (to make x alone) you will divide 14 by 2 ( sign of 2 changes from multiplication to division)

Final Step: x=7

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3 years ago

Which of the following represents The linear equation 3x+y=2 in slope-intercept form

ollegr [7]

C, see explanation in the picture attached below.

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3 years ago

The formula for the nth square number is S_n = n^2. Use the formula to find the 11th square number.

Klio2033 [76]

Answer:

121.

Step-by-step explanation:

$S_{11} = 11^{2} = 121.$ So, the 11th square number is 121.

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3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago

In a class of p students, the average (arithmetic mean) of the test scores is 70. in another class of n students, the average of

lys-0071 [83]

First case:

average of test score =70

number of students =p

total score of 'p' students = ( average of test score)*( number of students)

total score of 'p' students =70p

Second case:

average of test score =92

number of students =n

total score of 'n' students = ( average of test score)*( number of students)

total score of 'n' students =92n

total number of students = p+n

total average score =86

so, total score =86(p+n)

total score = total score of 'p' students +total score of 'n' students

$86(p+n)=70p+92n$

now, we can simplify it

$86p+86n=70p+92n$

$86p-70p=92n-86n$

$16p=6n$

now, we can find p/n

$\frac{p}{n}= \frac{6}{16}$

$\frac{p}{n}= \frac{3}{8}$ ................Answer

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3 years ago