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kumpel [21]
1 year ago
12

Directions: For the following systems, determine whether or not the ordered triple (1, -1, -2) is a solution to the equations be

low.
1. 3x – 3y – z = 2

2. 2x – 3y + z = -3

3. x + y + z = -2

4. x + 2y – z = 0

5. 5x – y – 5z = 16

6. 4x + 5y – 6z = -13
Mathematics
1 answer:
uranmaximum [27]1 year ago
8 0

Put the coordinate and check each

#1

\\ \rm\Rrightarrow 3x-3y-z=2

\\ \rm\Rrightarrow 3(1)-3(-1)-(-2)=2

\\ \rm\Rrightarrow 3+3+2=2

\\ \rm\Rrightarrow 6+2=2

\\ \rm\Rrightarrow 8\neq 2

No

#2

\\ \rm\Rrightarrow 2(1)-3(-1)-2=-3

\\ \rm\Rrightarrow 2+3-2=-3

\\ \rm\Rrightarrow 3\neq-3

Unless you did typing mistake on right hand side it's

  • No

#3

\\ \rm\Rrightarrow 1-1-2=-2

\\ \rm\Rrightarrow -2=-2

Yes

#4

\\ \rm\Rrightarrow 1+2(-1)-(-2)=0

\\ \rm\Rrightarrow 1-2+2=0

\\ \rm\Rrightarrow 1\neq0

No

#5

\\ \rm\Rrightarrow 5(1)+1-5(-2)=16

\\ \rm\Rrightarrow5+1+10=16

\\ \rm\Rrightarrow 16=16

Yes

#6

\\ \rm\Rrightarrow 4(1)+5(-1)-6(-2)=-13

\\ \rm\Rrightarrow 4-5+12=-13

\\ \rm\Rrightarrow -1+12=-13

\\ \rm\Rrightarrow 11\neq -13

No

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hope I helped, best wishes to your future studies...

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