First solve the equation by dividing 5 on both sides...
Y = 5\2x + 2
Now we want perpendicular and the line to flip across the axis so the answer is....
Y = -2\5 + 2
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.
The answer is no, the side lengths are not persevered. <span />
Answer:
11 Students
Step-by-step explanation:
It is hard to explain in my opinion but I can try. For the stem column you, basically factor out the first digit of the number. Then the leaf column you, put the second digit of each number in your data set.
Once you complete the square the equation is (x+3)^2 + (y - 8)^2 = 64
The center is (-3,8)
Radius is 8
A. False
B. True
C. False