To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Hello!
To find the volume of a cone you do
r is radius
h is height
Put in the values we know and 3.14 for pi
Multiply and you get 619.10
The answer is 619.10 cubic cm
400 quarters
$1 = 4q
4q • 100 = 400
400q=$100
The answer would be -5x-20+15/10
please can i have a brainliest
The correct answer here would be D. And that is because, in a triangle, the sum of 2 of the sides has to be greater than the third side for all sides. If we add 22 and 13 we get 35, and 35 is greater than 9, for sure. But if we add 13 and 9 we get 22 which is not greater than the third side length of 22; it would be collinear with the side length and it has to be greater than the side length.
