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1 year ago

Line segment AB has endpoints A(1,8) and B(7,−4). What are the coordinates of the point located 5/6 of the way from A to B?

Mathematics

1 answer:

const2013 [10]1 year ago

6 0

The coordinate of the point is (6,-2)

<h3>How to determine the coordinate of the point?</h3>

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

$(x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)$

So, we have:

$(x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)$

Evaluate

$(x,y) = \frac{1}{6}* (36 , -12)$

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

Read more abut line segment ratio at:

brainly.com/question/12959377

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