The given data is angle ∡RSU and angle ∡UST are complementary and
angle ∡RSU= 8k-1 and angle ∡UST = 7 (k-2)
The sum of the complementary angles is 90°
∡RSU + ∡UST = 90° => 8k-1 + 7 (k-2) = 90 => 8k-1+7k-14=90 => 15k - 15 = 90 => 15k = 90+15 => 15k = 107 => k= 105/15 = 7° then
∡RSU= 8k-1= 8*7-1= 55°
∡UST= 7 (k-2)= 7 (7-2)= 7*5= 35°
The correct answer is ∡RSU= 55° and ∡UST= 35°
Good luck!!!
Answer:
18
Step-by-step explanation:
- -3a²-b³+3c²-2b³
- -3(2)²-(-1)³+3(3)²-2(-1)³
- -3(4)-(-1)+3(9)-2(-1)
- -12+1+27+2
- -11+27+2
- 16+2
- 18
Answer:
2, 5, 8, 11, 14, 17
Step-by-step explanation:
rule = +3
Answer:
O lies on the perpendicular bisector of AB. ... Then, O' will lie on the perpendicular bisector PQ and RS. We know that, two lines cannot intersect at more than one point, So O' must coincide with O. Hence, there is one and only one circle passing through three non collinear points
Step-by-step explanation:
I will ask you to turn it in english instead of española.
