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Reptile [31]
2 years ago
7

In the year 1998, the surface elevation of Lake Powell was 3881 feet above sea level. In the year 2006, the surface elevation of

Lake Powell was 3263.4 feet above sea level.
Interpret the rate of change in this situation. The surface elevation of Lake Powell is decreasing at a rate of
Mathematics
1 answer:
Vesna [10]2 years ago
3 0

The surface elevation of Lake Powell is decreasing at the rate of 77.2 feet per year.

<h3>What is the rate(slope) at which the sea is decreasing?</h3>

The rate at which the surface elevation of the Lake Powell is decreasing can be determined by calculating the slope(steepness) of the sea.

The slope can be given as:

Slope (Δm) = rise/run

Slope (Δm)  = Δy/Δx

slope (Δm)  = y₂ - y₁/x₂-x₁

slope (Δm)  = 3263.4 - 3881/2006-1998

slope (Δm)  = -617.6/8

slope (Δm)  = -77.2

Therefore, we can conclude that the surface elevation of Lake Powell is decreasing at the rate of 77.2 feet per year.

Learn more about calculating the slope here:

brainly.com/question/1884491

#SPJ1

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1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
An isosceles triangle has an angle that measures 128°. Which other angles could be in that isosceles triangle? Choose all that a
aliina [53]

Answer:

Step-by-step explanation:

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The remaining angles must be 26° each.

4 0
3 years ago
Help! Based on the given information, what can you conclude and why?
DochEvi [55]

Answer: \triangle HIJ \cong \triangle LKJ

Step-by-step explanation:

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HJ ≅ JL

And, ∠HJI ≅ ∠ LJK

Therefore, By ASA postulate,

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This is why Option first is correct.

Note: Option third ΔHIJ≅ΔJKL is not correct,

Because,  HI≠JK



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Answer:

\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}

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How can you find the unit rate on a graph that goes through the origin?​
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Answer:

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Step-by-step explanation:

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