P = 2(L + W)
P = 150
L = 5W + 7
150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width
L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length
Answer: D) csc (2π/3)
<u>Step-by-step explanation:</u>
2π/3 is in Quadrant II
Quadrant II has a negative x-value and a positive y-value.
x-values are: cos & sec
y-values are: sin & csc
tan = y/x so will be negative in Quadrant II
A) sec = -
B) tan = -
C) cos = -
D) csc = + this works!
Answer:
1)B
Step-by-step explanation:
Answer:
Step-by-step explanation:
You can plug in the 294 for A and solve
