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kipiarov [429]
3 years ago
13

write an equation for the line that passes through (5,-4) and is perpendicular to the graph of 5x -2y=-6

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0

Answer:

y = (-2/5)x - 2

Step-by-step explanation:

One way to attack this problem is to interchange the coefficients of x and y and change the sign of one to +:  5x - 2y = -6 becomes 2x + 5y = c.  Solving for the slope, m, we get 5y = -2x + c first, and then y = (-2/5)x + D.

Subbing 5 for x and -4 for y, we now have -4 = (-2/5)(5) + D.

Then -4 = -2 + D, so that D = -2.

The desired equation is thus y = (-2/5)x - 2.

Check:  Does this pass through (5, -4)?  Is -4 = (-2/5)(5) - 2 true?  Yes.

Is the slope -2/5 the negative reciprocal of 5/2?  Yes, it is.


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5 0
3 years ago
Leslie and Surekha were standing on opposite sides of a road. Suddenly, they spotted a puppy stranded on the road and both rushe
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we can form a triangle to help us understand how to solve this problem:

                                                    puppy

∠ Leslie = 35°                                                   ∠ Surekha = 70°

If Leslie's angle is 35° and Surekha's angle is 70°, that gives us a total of 105°. Since the sum of the triangle's three angles is 180°, then the angle at which they will meet is 180° - 105° = 75°

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<h3>Solution:</h3>

\huge \pink {\tt {{128}^{ \frac{3}{7} }  =  \sqrt[7]{ {128}^{3} }  =  {2}^{3}  }}

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\huge \purple {\tt {8 \: is \: the \: answer}}

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3 years ago
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