Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The student is 6 feet tall. What is the height of the tree? Show all work
<em><u>Answer:</u></em>
Option D
The height of tree is 20 feet tall
<em><u>Solution:</u></em>
From given question,
Shadow of tree = 30 feet
Height of tree = ?
Height of student = 6 feet
Shadow of student = 9 feet
We have to find the height of tree
We can solve the sum by proportion

This forms a proportion and we can solve the sum by cross multiplying

Thus height of tree is 20 feet tall
Answer:
the answer is 7917.51cm^3 [OPTION A=7,922cm^3]
Step-by-step explanation:
radius=d÷2 41÷2 = 20.5, height=18cm
Volume=πr^2h÷3
=3.14×(20.5)^2×18÷3
=(3.14×20.5×20.5×18)÷3
=23752.53÷3
=7917.51cm^3
The area of a parallelogram is equal to the base multiplied by the height. Since we can see that this is a parallelogram (because of the two pairs of parallel sides), we now know how to find the area. Since we already know the height and the area, we can substitute their values into the formula to solve for the base.
8 * (the base) = 64
Divide each side by 8 to figure out the length of the base
the base = 8 in.
q = quarters
dimes is 3 plus 3times quarters
so 3q is 3 times quarters
so 3q+3 would be 3 times plus 3
equation is 3q+3
the value would be 10(3q+3)