Question

If the volume of a gas is 958 mL at 75.0 C, at what temperature would the volume of the gas decrease to 822 mL

Answer 1

75.0 degrees Celsius = 75.0 + 273 = 348 K.

Assuming pressure is held constant,

$\frac{958}{348}=\frac{822}{T_{2}} \\ \\ \frac{348}{958}=\frac{T_{2}}{822} \\ \\ T_{2}=\frac{(822)(348)}{958} \approx 299 \text{ K} \\ \\ T_{2} \approx 299-273=\boxed{26^{\circ} \text{ C}}$