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Marrrta [24]
2 years ago
9

If the volume of a gas is 958 mL at 75.0 C, at what temperature would the volume of the gas decrease to 822 mL

Chemistry
1 answer:
zhenek [66]2 years ago
3 0

75.0 degrees Celsius = 75.0 + 273 = 348 K.

Assuming pressure is held constant,

\frac{958}{348}=\frac{822}{T_{2}}  \\ \\ \frac{348}{958}=\frac{T_{2}}{822} \\ \\ T_{2}=\frac{(822)(348)}{958} \approx 299 \text{ K} \\ \\ T_{2} \approx 299-273=\boxed{26^{\circ} \text{ C}}

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Answer:

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First, you need to convert grams to moles using the molar mass.

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To find the volume, you need to use the Ideal Gas Law:

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In this equation,

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After converting the temperature from Celsius to Kelvin, you can plug the given values into the equation.

P = 1132 torr                                   R = 62.36 torr*L/mol*K

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PV = nRT

(1132 torr)V = (0.435 moles)(62.36 torr*L/mol*K)(364.15 K)

(1132 torr)V = 9888.015

V = 8.73 L

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