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Serjik [45]
3 years ago
13

Which statement describes the Arrhenius interpretation of acids and bases?

Chemistry
1 answer:
Vilka [71]3 years ago
5 0

Answer:

See Explanation

Explanation:

Note => 1st one should understand that for an 'acid' to be an acid and a 'base' to be a base, two requirements must be met, (1) the compound must have an ionizable Hydrogen for acids or Hydroxide for bases, and (2) must be in water and ionize delivering H⁺ ions from acids and OH⁻ ions from bases. The  Arrhenius acids are characterized by having an ionizable hydrogen which when added into water increases the hydronium ion concentration (H₃O⁺). Arrhenius bases are characterized by having an ionizable hydroxide function (OH-).

Typically, the acids and bases are characterized as either strong or weak  electrolytes. the Strong electrolytes ionize 100% in water and Weak electrolytes less than 100%.

The strong acids include HCl, HBr, HI, HNO₃, HClO₄ and H₂SO₄ (1st ionization step). Any acid (H-Anion) not a member of the strong 6 is a weak acid.

The strong Arrhenius Bases are Group IA and Group IIA Hydroxides except for Beryllium Hydroxide. Weak Arrhenius Bases are ammonia or ammonia derivatives (amines) in water.  

=> NH₃ + H₂O => NH₄OH ⇄ NH⁺ + OH⁻.

The ammonia derivatives follow the same reactive nature in water.

=> RNH₂ + H₂O => RNH₃OH ⇄ RNH₃⁺ + OH⁻ where R- is a structural substrate; e.g., Methyl Amine => H₃C - NH₂ .

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Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

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8 0
1 year ago
A geologist is studying the shore along a river. She finds a pile of rocks at the base of a riverbank. These broken rock pieces
Dmitry_Shevchenko [17]

The scientist who studies the earth constituent like solids, gas and liquid is called a geologist. Weathering and erosion are the correct blanks.

<h3>What are weathering and erosion?</h3>

The process of the deterioration of any solid particles like minerals, soils and rocks is called weathering. It occurs due to biochemical substances, atmospheric gases and water pressure.

The process of the transportation of the rocks and mineral particles away from their original position is called erosion it is due to forceful air and water.

The rocks moved from their original place to some another due to weathering and this process of their transportation is called erosion.

Therefore, <u>weathering </u>and <u>erosion </u>are the correct blanks.

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7 0
2 years ago
Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working
solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = 0.0821Latm/Kmol

T =temperature =273K   (at STP)

V=\frac{nRT}{P}

V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}

V=15.3L

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0
3 years ago
What is the result of cooled, solidified lava?
Dahasolnce [82]
Cooled, solidified lava is called igneous rocks.
8 0
4 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
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