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ahrayia [7]
3 years ago
12

97.2 kJ of heat is added to a 12.0 kg block or iron. what is the temperature change of the block?

Chemistry
1 answer:
irina [24]3 years ago
3 0

Answer:

\Delta T=18.24\°C

Explanation:

Hello,

In this case, since the equation for computing the heat in terms of mass, specific heat and temperature change is:

Q=mCp\Delta T

For the given heat and mass, and considering the specific heat of iron to be 0.444 kJ/(kg°C), the resulting temperature change is:

\Delta T=\frac{Q}{mCp}=\frac{97.2kJ}{12.0kg*0.444\frac{kJ}{kg\°C}}\\  \\\Delta T=18.24\°C

Best regards.

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