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forsale [732]
2 years ago
7

Juan plays 2 hours of video games per day. How many hours does he play in 6 days?

Mathematics
1 answer:
Ber [7]2 years ago
3 0
One day = 2 hours
6 days = 2 * 6 = 12 hours

You have to multiply hours he plays per one day with 6 days.
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What is the slope of y =2x-1​
katen-ka-za [31]

Answer:

<h2>The slope m = 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

<em>y = mx + b</em>

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the equation:

<em>y = 2x - 1 → m = 2, b = -1</em>

5 0
3 years ago
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Hi everyone I needs ton of help!
Svet_ta [14]

Answer:

1/4

Step-by-step explanation:

7 0
3 years ago
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There are nine empty seats in a theater, and six customers need to find places to sit. How many different ways can these six sea
dybincka [34]

Answer: 60480

Step-by-step explanation:

Given : The number of empty seats in a theater = 9

The number of customers need to find places to sit =6

Since order matters here, so we use permutations

The permutations of n things taking r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of ways to arrange 6 seat in 9 seats :-

^9P_6=\dfrac{9!}{(9-6)!}=\dfrac{9\times8\times7\times6\times5\times4\times3!}{3!}\\\\=60480

Hence, the number of ways to arrange 6 seat in 9 seats = 60480

3 0
3 years ago
A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
3 years ago
Need help please and thank you
Juli2301 [7.4K]
It would be C because it’s asking you to multiple 3/4 by 3/4 sense there is a 2 exponent. And in order to multiply fractions you multiply across the top and bottom and then simplify. Sense c is already simplified that would be your answer. 3 x 3
4x4 9/16 or c
3 0
3 years ago
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