Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3
Answer:
8-42 = -34 will be applied
Answer:
18x
Step-by-step explanation:
18x times 18x
so the side is 18x because it was squared
There are no solutuons listed (says which of the following). My answer below should be in the list to choose from.
7 - 4x ≥ 35
subtract 7 from both sides
-4x ≥ 28
divide both sides by -4 AND change the direction of the inequality sign because we're dividing by a negative
x ≤ -7
CHECK:
7 - 4x ≥ 35
7 - 4(-7) ≥ 35
7 + 28 ≥ 35
35 ≥ 35
ANSWER: x ≤ -7
Hope this helps! :)
Answer:
Step-by-step explanation:
Given the first two numbers of a sequence as 2, 6...
If it is an arithmetic difference, the common difference will be d = 6-2 = 4
Formula for calculating nth term of an ARITHMETIC sequence Tn = a+(n-1)d
a is the first term = 2
d is the common difference = 4
n is the number if terms
Substituting the given values in the formula.
Nth term Tn = 2+(n-1)4
Tn = 2+4n-4
Tn = 4n-4+2
Tn = 4n-2
2) If the sequence us a geometric sequence
Nth term of the sequence Tn = ar^(n-1)
r is the common ratio
r is gotten by the ratio of the terms I.e
r = T2/T1
r = 6/2
r = 3
Since a = 2
Tn = 2(3)^(n-1)
Hence the nth term of the geometric sequence is Tn = 2(3)^(n-1)
