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2 years ago

How many grams of magnesium

Chemistry

1 answer:

nalin [4]2 years ago

3 0

Answer:

73 g Mg(OH)₂

Explanation:

To find the mass of magnesium hydroxide, you need to (1) convert formula units to moles (via Avogadro's number) and then (2) convert moles to grams (via molar mass). Remember to arrange the conversions/ratios in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 2 significant figures because the given value (7.5 x 10²³) has 2 sig figs.

Avogadro's number:

6.02 x 10²³ formula units = 1 mole

Molar Mass (Mg(OH)₂):

58.32 g/mol

7.5 x 10²³ units Mg(OH)₂ 1 mole 58.32 g
----------------------------------- x ---------------------------- x -------------------- =
6.02 x 10²³ units 1 mole

= 73 g Mg(OH)₂

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4 years ago

An experiment was set up to test the hypothesis that all plants will grow faster in a "super soil" versus regular potting soil.

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4 years ago

An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +

Maurinko [17]

Answer:

The simplified expression for the fraction is $\text {X} = \dfrac{ {k_3 \times cM} }{k_1 +k_2 + k_3 }$

Explanation:

From the given information:

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where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

$\text {X} = \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) } } }$

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$\text {X} = \dfrac{ {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3 \times cM) }$

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4 years ago

Find the empirical formula of the following compounds:

Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus $\frac{mol phosphorus}{ 30.97 g phosphorus}$ = 0.0293 mol

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The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

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8 0

1 year ago

A cubic piece of metal measures 3.00 cm on each edge. If the metal is nickel, whose density is 8.90 g/cm3, what is the mass of t

blsea [12.9K]

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D = m / V

8.90 = m / 27

m = 8.90 x 27

m = 240.3 g

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3 years ago