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notsponge [240]
3 years ago
7

7. A scientist is trying to determine the identity of an element. It is highly reactive in water

Chemistry
1 answer:
Hunter-Best [27]3 years ago
7 0
Group 15 is the correct answer
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Which best describes an element? A pure substance. A type of a mixture. A pure compound. An impure substance.
mr Goodwill [35]

a pure compound because an element is untouched and is just itself

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3 years ago
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you produce 115 grams of water in a combustion reaction. how much methane do you need in grams for this to react?
lora16 [44]

Answer:about 2 grams of methane

Explanation:

idk just got this right

6 0
3 years ago
Samuel adds a teaspoon of salt to a glass of water. He notices that the salt disappears. Samuel takes a sip to discover that the
Vera_Pavlovna [14]

Answer:

B

Explanation:

B It’s a physical change because the water and the salt kept their original properties.

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Name of these two Alkanes
fgiga [73]
3-ethyl-5,6-dimethyloctane

3-ethyl-2,3-dimethylpentane
5 0
3 years ago
Determina el grado de pureza de un marmol (CaCO3), si al descomponerse 125 g del mismo se desprenden 20 litros de dióxido de car
jarptica [38.1K]

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

<em>Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.</em>

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

<em>Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). </em>Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = <em>84.7g de CaCO₃</em>

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100<em> = </em>

<h3>67.8%</h3>
7 0
3 years ago
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